Question 13015 of 749 · Maryland Journeyperson Electrician Exam
A single-phase 240 volt load draws 50 amperes, and a wattmeter reads 10.2 kW. What is the power factor?
Exactly one answer is correct.
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Correct answer to question 13015
- C: 0.85
Explanation
Apparent power is 240 x 50 = 12,000 VA, so PF = W / VA = 10,200 / 12,000 = 0.85. A power factor above 1.0 (1.18) results from dividing VA by W and cannot occur.
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