Question 13002 of 749 · Maryland Journeyperson Electrician Exam
A 4,800 watt resistive water heater is connected to a 240 volt single-phase circuit. What is the current?
Exactly one answer is correct.
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Correct answer to question 13002
- B: 20 A
Explanation
For a single-phase resistive load, I = P / E = 4,800 W / 240 V = 20 A. Using 120 V gives 40 A, and applying the three-phase factor 1.732 gives 11.5 A or 34.6 A, both wrong for a single-phase load.
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