Question 12028 of 871 · Maryland Journeyperson Electrician Exam
Standard method (NEC 2020/2023), 120/240 V: 2,400 ft2 dwelling, two small-appliance and one laundry circuit, 1,200 VA dishwasher, 900 VA disposal, 4,500 W water heater, 1,000 VA trash compactor, 12 kW range, 5.5 kW dryer, 9 kW electric heat and 4,800 VA AC. What is the minimum calculated service load in amperes?
Exactly one answer is correct.
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Correct answer to question 12028
- D: 142.7 A
Explanation
Lighting/SA/laundry 11,700 VA with demand = 6,045 VA; four fixed appliances 7,600 VA x 75 % = 5,700 VA; range 8,000 VA; dryer 5,500 VA; heat 9,000 VA (AC omitted as noncoincident). Total 34,245 VA / 240 V = 142.7 A (lighting load 220.14(J) in 2020 or 220.41 in 2023, Table 220.42 in 2020 or Table 220.45 in 2023, 220.53, Table 220.55).
More questions: Load Calculations
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