Question 12093 of 749 · Maryland Journeyperson Electrician Exam
NEC 2020/2023 220.83(A): an existing 1,600 ft2 dwelling with two small-appliance and one laundry circuit, a 12 kW range, 5 kW dryer and 4.5 kW water heater gets no new heating or AC. What is the calculated load?
Exactly one answer is correct.
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Correct answer to question 12093
- A: 17,120 VA
Explanation
Total load = 4,800 lighting (3 VA/ft2) + 4,500 + 12,000 + 5,000 + 4,500 = 30,800 VA. 220.83(A) takes the first 8 kVA at 100 % and the rest at 40 %: 8,000 + 22,800 VA x 0.4 = 17,120 VA.
More questions: Load Calculations
- 12094NEC 2020/2023 220.83(B): an existing 2,000 ft2 dwelling (two small-appliance and one laundry circuit, 11 kW range, 5.5 kW dryer) adds a 6,000 VA central AC. What is the calculated load?
- 12095Under NEC 2020/2023 220.83, what portion of the existing general load is counted at 100 % before the 40 % factor applies?
- 12098Which is a condition for using the NEC 2020/2023 multifamily optional method of 220.84?
- 12099An existing 200 A service shows a 1-year maximum demand of 110 A. A 40 A load is added. Using NEC 2020/2023 220.87, what is the resulting calculated load?
- 12101Under NEC 2020/2023 220.60, a dwelling has 10 kW of electric heat and a 5,000 VA AC unit that do not run together. What load is used in the standard method?
- 12102An 8-unit building has 900 ft2 units, each with two small-appliance and one laundry circuit. What is the NEC 2020/2023 standard method demand for these loads?